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3.25x^2=9
We move all terms to the left:
3.25x^2-(9)=0
a = 3.25; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·3.25·(-9)
Δ = 117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{117}=\sqrt{9*13}=\sqrt{9}*\sqrt{13}=3\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3\sqrt{13}}{2*3.25}=\frac{0-3\sqrt{13}}{6.5} =-\frac{3\sqrt{13}}{6.5} =-\frac{\sqrt{13}}{2.1666666666667} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3\sqrt{13}}{2*3.25}=\frac{0+3\sqrt{13}}{6.5} =\frac{3\sqrt{13}}{6.5} =\frac{\sqrt{13}}{2.1666666666667} $
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